Question: Explain how you would prepare each of the following hydrogen peroxide (solute) and normal saline (solvent) irrigation orders:
1L of 1/4 strength solution
1L= 1q = 32 fl oz = 2pt = 960 mL (is this correct?)
The question is asking for an answer in mL.
The book's answer is:
250 mL hydrogen peroxide (solute) + 750 mL normal saline (solvent) = 1,000 mL (1L) of the 1/4 strength solution.
How does 1,000 mL = 1L when I calculated 32 fl oz x 30 mL = 960 mL?
for my answers I got: 240 mL solute (hydrogen peroxide) and 720 mL solvent (normal saline) = 960 mL total solution = 1L right?
I'm really confused with these calculations.