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Does anyone know the answer to G-5 T-3 P-3 A-1 L-5? (GTPAL question)
G= 5 pregnancies
T=3 term babies
P=3 pre-term babies
A=1 miscarriage or abortion
L= 5 living children
I could be wrong, but if you talk it out... she has been pregnant (total) of 5 times and had one abortion. So, out of 5 pregnancies 4 were delivered after 20 weeks. She has had 6 babies after 20 weeks, that means either 1 set of triplets and 3 singleton births, or 2 sets of twins and 2 singleton births... either way 1 baby died after 20 weeks.
G= number of pregnancies, so in this case 5 actual pregnancies (it doesn't matter how many babies per pregnancy)
T= the number of births at term (37 weeks or more). In this case 3
P= preterm births (before 37 weeks yet viable). so in this case 3 births were viable and preterm
Well how does T+P=a number greater than G? do not confuse pregnancies with births.
WE need to think it out.
If A= biological children that were Aborted (spontaneous or electively), in this case 1. A still counts toward pregnancy (G)
we only have a L of 5. L= living children, despite 7 possible babies (T+P+A)
So, 5 pregnancies, 1 aborted or non-viable birth which could have been a twin that did not make it-which is common. I am guessing she had two sets of twins where in one set, one died, and then 3 single pregnancies. I am pretty sure, but let me know if you find an error.
One more thing. P in this case =preterm. Wehn you are thinking of parity, that is the number of actual births. sometimes the letters are GPTPAL, but rarely. Usually if parity is considered, as in actual hospital paperwork, then they write it out. Also, someone might ask, "what is her parity?" which is like asking, "what is her GTPAL?" That would sound weird. So, they ask, "what is her parity?" and you would respond, "She is a G5, T_, ..." . let me know if that helps. Good luck.
Ok, so 3T + 3P + 1A=7 children total. But there are only 5L. There is the 1 Abortion, meaning 1 child was miscarried or electively aborted BEFORE 20weeks. This is where it gets tricky because there are 2 children and 1 is unaccounted for right now. preterm means births before 37 weeks BUT ALSO includes "stillborns/stillbirths" that term medically means losing the baby during labor after 20 weeks or "miscarrying" after 20 weeks. So this mom Had 1 elective abortion or miscarried before 20 weeks. And since 2 children died the other one died during labor or she "miscarried" after 20 weeks (patients still have to deliver the fetus or have it removed...both of which dilation &/or contractions occur...so that is classified as a preterm birth.) **OR a child preterm or full term was born alive and died later. And as far as which died when you won't know that by lookin at the chart. She could have been preg with twins twice and 3 singles OR triplets and 4 singles OR is currently pregnant with previous set of triplets, set of twins, and 2 singlesG= number of pregnancies, so in this case 5 actual pregnancies (it doesn't matter how many babies per pregnancy)T= the number of births at term (37 weeks or more). In this case 3P= preterm births (before 37 weeks yet viable). so in this case 3 births were viable and pretermWell how does T+P=a number greater than G? do not confuse pregnancies with births.WE need to think it out. If A= biological children that were Aborted (spontaneous or electively), in this case 1. A still counts toward pregnancy (G)we only have a L of 5. L= living children, despite 7 possible babies (T+P+A)So, 5 pregnancies, 1 aborted or non-viable birth which could have been a twin that did not make it-which is common. I am guessing she had two sets of twins where in one set, one died, and then 3 single pregnancies. I am pretty sure, but let me know if you find an error.
obpedsrnstudent
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Does anyone know the answer to G-5 T-3 P-3 A-1 L-5? (GTPAL question)