Diluting propofol in lidocaine

by nurs1ng (Member)

6,191 Visitors; 149 Posts

Putting 5 cc of 1% propofol into a 10 ml syringe and mixing it with 5 cc 1% lidocaine... what would that give me X mg/ml of propofol? Just wanna make sure I have my calculations right. Any help would be appreciated

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All you need to figure out is how many milligrams/ml of Propofol are in a 1% solution. It matters not how you dilute it. The dose won’t change only the concentration will.

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6,191 Visitors; 149 Posts

1 hour ago, Wuzzie said:

All you need to figure out is how many milligrams/ml of Propofol are in a 1% solution. It matters not how you dilute it. The dose won’t change only the concentration will.

So that would give me 2 mg/ml? I know that 1% is 10 mg/ml.. what's confusing me is if there would be a difference with taking 1 cc of 1% vs 5 cc of 1% but from your post, seems like there is no difference as to how much you take out since 1% will be constant from the get go.

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4 Followers; 17,976 Visitors; 2,757 Posts

Show me how you got 2mg/ml so I can see where you’re getting hung up.

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6,191 Visitors; 149 Posts

1 hour ago, Wuzzie said:

Show me how you got 2mg/ml so I can see where you’re getting hung up.

Well initially I got 5 mg/ml (5 cc of 1% prop in 5 cc lido)...but may have misinterpreted your post and so my other answer concluded to 2 mg/ml (1 cc 1% prop divided by 5 cc lido = 2 mg/ml)

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One of our members, a retired pharmacist, has written a textbook (Pharmacy Calculations for Pharmacy Technicians) that he has made available.  Although written for pharmacy technicians most of the material is applicable to nursing as well.  If you are not familiar with dimensional analysis you might find it helpful.

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MunoRN has 10 years experience and works as a Critical Care.

63,669 Visitors; 6,068 Posts

You might be overthinking this.  You know you've got 5ml of 10mg/ml Propofol, and you know your final volume.  So how many mgs of Propofol are in that final volume?

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It looks like you have 50 mg in 10 mL = 5mg/mL of propofol in the mixture.