Another Drug Dosage Question

Nursing Students Student Assist

Published

Okay. I have looked all over the internet and haven't been able to find a question quite like this, or at least not close enough to help me understand it. I have flipped through the forums here, but there are a lot of drug dosage posts and the ones I did look at didn't help me. Hopefully someone here can or at least point me somewhere that can answer my question. Of course, it may be simple and I'm just so fried I cannot wrap my head around this. :confused:

Problem:

Shawn is to receive 350 ml D5 1/4 NS with 2 mEq KHPO4/100ml of fluid over a 24 hour period. The fluid is available only in 250 ml bags. How much KHPO4 will you add to each bag?

Answer:

1.7 ml

WHAT?!? :banghead:

Next Problem:

Joe is receiving 2800 ml D5 1/2 NS with 20 mEq KCL/L/Day. The fluid is available only in 500 ml bags. The KCL is labeled 30 mEq/10ml. How much KCL will you add to each bag?

Answer:

3.3 ml

Please help me!

Thanks,

Crissanne

Before I work these, are you 100% positive that's the correct problem and what it's asking for? Some threads have info missing or a typo that throws it off...double check real quick

Specializes in Med/Surg/Pedi/Tele.

God I'm taking this class in September and I hope it makes sense to me... right now this all sounds like gibberish! lol

Yes! I doubled checked myself...3 times. I just know that the first problem is missing vital information, LIKE THE LABEL. I just wanted to make sure. Driving me nuts!

Specializes in med/surg, telemetry, IV therapy, mgmt.

problem #1: shawn is to receive 350 ml d5 1/4 ns with 2 meq khpo4/100ml of fluid over a 24 hour period. the fluid is available only in 250 ml bags. how much khpo4 will you add to each bag?

your answer you were given must be wrong. i keep getting an answer of 1.4. this is a ratio. set up the equation:
2 meq in 350 ml = x meq in 250 ml and solve for x
.
the answer is
1.4 meq
.

problem #2: joe is receiving 2800 ml d5 1/2 ns with 20 meq kcl/l/day. the fluid is available only in 500 ml bags. the kcl is labeled 30 meq/10ml. how much kcl will you add to each bag?

500 ml d5 1/2 ns (fluid on hand)/1 x 20 meq/1 l (dose desired) x 10 ml/30 meq (dose on hand) x 1 l/1000 ml (conversion factor) =
3.3 ml
(amount of kcl to add to each 500 ml bag)

problem #1: shawn is to receive 350 ml d5 1/4 ns with 2 meq khpo4/100ml of fluid over a 24 hour period. the fluid is available only in 250 ml bags. how much khpo4 will you add to each bag?

your answer you were given must be wrong. i keep getting an answer of 1.4. this is a ratio. set up the equation:
2 meq in 350 ml = x meq in 250 ml and solve for x
.
the answer is
1.4 meq
.

problem #2: joe is receiving 2800 ml d5 1/2 ns with 20 meq kcl/l/day. the fluid is available only in 500 ml bags. the kcl is labeled 30 meq/10ml. how much kcl will you add to each bag?

500 ml d5 1/2 ns (fluid on hand)/1 x 20 meq/1 l (dose desired) x 10 ml/30 meq (dose on hand) x 1 l/1000 ml (conversion factor) =
3.3 ml
(amount of kcl to add to each 500 ml bag)

that's why i was asking about number 1 having any missing info...i kept getting 1.4meq and the op said the answer was 1.7 ml...

but daytonite, i was wondering if we may have missed something. because if there are 2meq per 100ml...then there would have to be 7 meq per 350ml. and no less than 5 meq per bag. but they said the answer was in ml, not meq...

but they said the answer was in ml, not meq...

my point exactly. i think this problem is missing the label information: xmeq / xml

thanks guys. after my post, i figured out the second one. really easy. just must have been fried and break was exactly what i needed.

thank you so much for you help!

Yeah the first question is missing something. I believe the original concentration of K phos is missing.

Here's my question for the first problem: WHICH BAG OF FLUID IS AVAILABLE IN ONLY 250 mL? The 350 D5 1/4NS (which I've never heard of - bet it's D5 1/2 NS, but that's irrelevant, it could be chicken broth for all I care), or the 100 mL w/ the K-Phos (whose formula, just to be pedantic and because I took 2 years of chemistry w/a year of organic, is actually K3PO4, and the other is actually potassium hydrogen phosphate, a buffer for specific chemical reactions that's measured in millimoles, not mEqs)?

You can't solve it without that being answered, and I think THAT'S the missing piece of information.

My point in my post is there's a lot of screwy information there already, so it's not too much of a stretch to imagine there's more missing information...

Missing info....yep there is. And D5 1/4 NS is actually possible. It's a hypertonic solution, but still irrelevant because something is missing.

+ Add a Comment