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ACUTE MI -PT/INR results! I need explanation!



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Sep 03, 2008 02:01 PM

ACUTE MI -PT/INR results! I need explanation!


PT/INR 0.6 seconds/1.8

I understand anything over 1 is high for INR and the patient is at risk for bleeding but I cannot find and explanation for reduced PT other than I think the clot forms too rapidly. Am I on the right track. why does this information contradict


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10 Comments
No. 1
from dianah
Old Sep 03, 2008, 03:01 PM

Default Re: ACUTE MI -PT/INR results! I need explanation!
I googled PT and protime and didn't come up with anything that makes sense of the values posted.

Is it possible there is/was an error (human or machine) error in obtaining/running them???
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No. 2
Old Sep 03, 2008, 03:21 PM

Default Re: ACUTE MI -PT/INR results! I need explanation!
Originally Posted by dianah View Post
I googled PT and protime and didn't come up with anything that makes sense of the values posted.

Is it possible there is/was an error (human or machine) error in obtaining/running them???

This is a school book question! At least I know Im not crazy LOL I looked at that for an hour good lord!! I think I am going crazy Thank you for your support
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No. 3
from ghillbert
Old Sep 03, 2008, 06:20 PM

Default Re: ACUTE MI -PT/INR results! I need explanation!
I've never seen a PT of 0.6 - sounds very odd.
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No. 4
from adria37
Old Sep 03, 2008, 07:06 PM

Default Re: ACUTE MI -PT/INR results! I need explanation!
That has to be a mistake IMHO to have a PT of .06 and INR of 1.8

INR = PT- test/PT-normal


Normal is roughly 1 and blood that takes twice as long to clot than "normal" would be 2. I would question the test.
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No. 5
from adria37
Old Sep 03, 2008, 07:13 PM

Default Re: ACUTE MI -PT/INR results! I need explanation!
I don't believe a protime is not measured in seconds either
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No. 6
from al7139
Old Sep 04, 2008, 03:17 AM

Default Re: ACUTE MI -PT/INR results! I need explanation!
Hi,
Hope this helps:
The PT (Prothrombin Time) is the amount of time needed to form a clot. It is measured in seconds. The INR (International Normalized Ratio) is a special mathematical calculation of the PT, used to monitor the effect of oral anticoagulants. For the patient getting PO therapy with Coumadin (Warfarin), the therapeutic range of the INR is 2.0 to 3.0. If the pt has a mechanical heart valve the therapeutic range of the INR is 2.5-3.5.
Although the test done includes BOTH the PT and INR, it is the INR that we use most often, because it is standardized across the world.
We monitor the PT/INR to determine the effect of anticoagulant therapy. If it is too low, ther is a risk for thrombus (clot) formation. If the level is too high, there is a risk for hemorrhage. In a normal person who does not need anticoagulants, the levels should be the PT is 10-14 seconds, and the INR should be 1.00-1.30.
In a pt with an MI, you would want the INR to be 2.0-3.0.
Hope this helps.
Amy
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No. 7
Old Sep 04, 2008, 08:07 AM

Default Re: ACUTE MI -PT/INR results! I need explanation!
Yes, very understandable thank you for that. The patient did have an acute MI.
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No. 8
from gradRN2007
Old Sep 13, 2008, 11:38 AM

Default Re: ACUTE MI -PT/INR results! I need explanation!
probably was a clotted specimen or short, most likely clotted.
should of been asked for a redraw from your lab
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No. 9
from EMT-Elvis
Old Sep 04, 2009, 03:13 AM

Default Re: ACUTE MI -PT/INR results! I need explanation!
curiousforlife, what school do you go to? I am working on the same question now...
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