Algebra help please

Aug 7, '0316x=8
x=8/16
x=1/2
i don't know what the second equation means (is that saying x the the something power times 2x minus 6???
good luck! 

Aug 7, '03Ok, then you're going to have to factor:
x2x6=0
(x3)(x+2)=0
x=3 or x=2
hope that helps!
kim 

Aug 7, '03Originally posted by Lisa1970
Ty the second reads x(secondpower)X6=0
0^06=0
Zero to the power of anything will always be zero. At least that's what I think would be the case. It's been awhile since I did this stuff... 
Aug 7, '03Okay, I don't think I understood the problem correctly. Ignore my answer because I am obviously more confused than anyone else...

Aug 7, '032ner has the right answer according to my answer sheet, but I am still unclear on how she did it

Aug 7, '03Is the equation x2x6=0? (for some reason that's what I assumed it was since I didn't see a sign in between the exponent and the 2nd x.
If so, you hafta factor....
(x3)(x+2) is equal to x2x6 you can figure it out by foiling the (x3)(x+2).
after you foil you get x2+2x3x6 which is the same as x2x6
then you have two terms that equal zero
you have x3=0 AND x+2=0
then you have to isolate the x's by adding three to both sides of the first term you get x=3 and by subtracting the 2 from both sides of the second term you get x=2
If the equation is x2 + x  6 = 0 then it factors out to be (x+3)(x2) and then the answers would b x=3 or x=2
does that make sense?
kimLast edit by 2ner on Aug 7, '03 
Aug 7, '03You have to use logs for the second problem.
x^2x 6=0
x^2x=6
logx^2x=log6
2x (logx)=log6
I don't have my calculator with me right now but then plug it in and then you can solve for x. I hope that helps (and I hope that's right )
Keely 


Aug 7, '03So 2nr has the correct answer? If so, then there is a misprint in this problem (actually in both...but I'll get there). If the answer to the second problem is x=3 or x=(2) then the problem should read the way 2nr interpreted it: x(squared)  x  6 = 0. It seems like you are missing a minus sign in the original problem.
As for the first problem, the answer is only 1/2 if the equation is equal to 0. (i.e. 16x  8 = 0). In the way it is written above, it is actually unsolvable.
PJ