Algebra help please

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I have two equations that I just can't figure out. Can someone look and see if they can tell me how to figure them?

16x-8=

x^2x - 6 = 0 then x is ?

I have to be able to solve these for the admission exam on Tuesday Thanks

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16x=8

x=8/16

x=1/2

i don't know what the second equation means (is that saying x the the something power times 2x minus 6???

good luck!

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Ty the second reads x(secondpower)X-6=0

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Ok, then you're going to have to factor:

x2-x-6=0

(x-3)(x+2)=0

x=3 or x=-2

hope that helps!

kim

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at the risk of looking really dumb (x-3)(x+2)=0 where did this come from?

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Specializes in CICu, ICU, med-surg.
Originally posted by Lisa1970

Ty the second reads x(secondpower)X-6=0

Hmmm...Wouldn't zero work?

0^0-6=0

Zero to the power of anything will always be zero. At least that's what I think would be the case. It's been awhile since I did this stuff...

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Specializes in CICu, ICU, med-surg.

Okay, I don't think I understood the problem correctly. Ignore my answer because I am obviously more confused than anyone else... :)

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2ner has the right answer according to my answer sheet, but I am still unclear on how she did it

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Is the equation x2-x-6=0? (for some reason that's what I assumed it was since I didn't see a sign in between the exponent and the 2nd x.

If so, you hafta factor....

(x-3)(x+2) is equal to x2-x-6 you can figure it out by foiling the (x-3)(x+2).

after you foil you get x2+2x-3x-6 which is the same as x2-x-6

then you have two terms that equal zero

you have x-3=0 AND x+2=0

then you have to isolate the x's by adding three to both sides of the first term you get x=3 and by subtracting the 2 from both sides of the second term you get x=-2

If the equation is x2 + x - 6 = 0 then it factors out to be (x+3)(x-2) and then the answers would b x=-3 or x=2

does that make sense?

:)

kim

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You have to use logs for the second problem.

x^2x -6=0

x^2x=6

logx^2x=log6

2x (logx)=log6

I don't have my calculator with me right now but then plug it in and then you can solve for x. I hope that helps (and I hope that's right:D )

Keely

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Okay, never mind. I thought the problem was x to the power of 2x minus 6. Whoops. :D

Keely

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the exact equation is x small 2 (above x) x - 6 = 0, then x is

X2 x - 6 = 0, then x is

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