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While doing practice questions for the NCLEX, I got confused on this one, can anyone enlighten me? thanks
A physician prescribes 1000 mL of 5% dextrose in water containing 1.5 mEq of KCl per 100 mL to infuse at a rate of 110 mL per hour.
At 7:00 am, the nurse hangs the solution
at 11:00 am, how much KCl has the client received?
thanks guys.
Maybe this is the long way and is different from what others have suggested but,
Given: -1000ml of solution
-1.5mEq kcl per 100ml= 15mEq kcl total in 1000ml
Question wants to know how much kcl per 110ml so I asked myself how long would it take 1000ml to run at 110ml/hr. 1000ml/110=9.0909 hrs
Now take your total kcl of 15 which is in the 1000ml of solution and divide it by 9.0909hrs.
15/9.0909=1.6500017 this equals the amount of kcl in mEq that will run at 110ml/hr.
Now you can multiple that number by any time frame you want.
So...110ml/hr of solution with 1.65mEq kcl will deliver a total of 440ml with 6.6mEq kcl in 4hrs.
this way might be a little easier for you to understand...
you are given that the bag is 1000ml containing 1.5ml per 100ml.
you are also given that the concentration is 1.5 ml kcl / 100ml this means that your total amount of the kcl in the bag is 15ml/1000ml (just multiply top and bottom by 10).
your rate is 110ml/hr.
from 7am to 11am you have 4 hours.
this means the total amount pumped at 11am is
4hr x 110ml/hr = 440ml
now take the part volume/total volume = part kcl/total kcl
this is 440ml/1000ml = xmeq/15meq
multiply both sides of the equal sign by 15
x = (15x440)/1000.
this works out to be x=6.6meq.
FreeMilo
18 Posts
the answer is 6.6