Word problems/mixture

Tonyapate · Jun 18, 2009

Me too...............! Jesus help us!.

nnicolee · Jun 18, 2009

Hey would you mind posting an example of a question so I can try to help you out?

Also, check out this web address they explain how to handle mixture problems! :)

Tonyapate · Jun 18, 2009

Can you help me???? Here is one I am stuck at. I just don't get the operation I am suppost to follow.

This year, 75% of the graduating class of Harriet Tubman High School had taken at

least 8 math courses. Of the remaining class members, 60% had taken 6 or 7 math

courses. What percent of the graduating class had taken fewer than 6 math courses?

nnicolee · Jun 18, 2009

Can you help me???? Here is one I am stuck at. I just don't get the operation I am suppost to follow.
This year, 75% of the graduating class of Harriet Tubman High School had taken at
least 8 math courses. Of the remaining class members, 60% had taken 6 or 7 math
courses. What percent of the graduating class had taken fewer than 6 math courses?

Okay, the way I would figure this problem out is by writing out a list of information as follows

75%- 8 COURSES

60%- 6 OR 7 MATH COURSES

?- FEWER than 6

What you have to understand is if students have taken 8 courses then that means they've taken 6 or 7 courses (I think that's understandable enough). So in order to figure out who's completed less than 6 courses all you have to do is subtract 60% (the students who've taken 6 or seven) from 100% which is 40%. So 40% of students have taken 6 or fewer math courses.

What you'll see in this problem is that the 75%/8 courses is not needed. All you really need to know is HOW MANY have take 6or7 courses.

Tonyapate · Jun 18, 2009

Thank you, Thank you, Thank you!:bowingpur

I was so stuck. I am really Thankful for people like you that care enough to help. :bow:

Miss Mab · Jun 18, 2009

um, well.....

Honestly I appreciate when anyone trys to help someone else when they're feeling stuck---especially on these kind of brain freeze ?'s---but I kinda think you might've got a little ahead of yourself there too, Nicole.

So, I read it as 'we know that the 75% are out because 8>6, and we also know that of the remaining 25% of the class(75+25=100% of class) that 60% of them had at least 6 classes. Now we need to know who had

Looks like we should see that 40% of that remaining 25% has taken fewer than 6. Well, because we have a nice and even breakdown of #'s to make the 100% (and don't ya love when that happens) all we REALLY need to know now is:

What is 40% of 25?

I do believe that there 10 students who had

I didn't set up the equation as these were small'ish and easily divisible, etc. But does the part where you actually get down to the real question of these wordy ones make more sense?

:)

nnicolee · Jun 18, 2009

um, well.....
I do believe that there 10 students who had
I didn't set up the equation as these were small'ish and easily divisible, etc. But does the part where you actually get down to the real question of these wordy ones make more sense?
:)

I do believe the question said percent... not number of people....

Can you help me???? Here is one I am stuck at. I just don't get the operation I am suppost to follow.
This year, 75% of the graduating class of Harriet Tubman High School had taken at
least 8 math courses. Of the remaining class members, 60% had taken 6 or 7 math
courses. What percent of the graduating class had taken fewer than 6 math courses?

Miss Mab · Jun 18, 2009

Ok, ummmm...

Then my answer's still...

wait for it...

10.

Sheesh....

nnicolee · Jun 18, 2009

Ok, ummmm...
Then my answer's still...
wait for it...
10.
Sheesh....

wow I feel like an absolute idiot. I forgot to take 40% and multiply it by 25% which IS 10%... i skipped way ahead of myself ther. I'm sorry for the confusion tony and miss mab...

*slap*

Tonyapate · Jun 19, 2009

Well, thanks both of you for the help anyways. I appreciate it.