Fun mEq Problem for you Math Junkies!

Hi All,
I haven't seen any math problems posted lately, so here is one to try.
You have 2.5 L of 10% NaCl solution and your friend has 1.5 L of MgSO_{4} solution.
You have twice as many mEq of NaCl as your friend has of mEq of MgSO4.
What is the percentage strength of your friend's MgSO_{4}?
Brad
p.s. This is not my homework! Ha. 



Feb 132500 X.1=250
250/2= 125
125/1500=.083333
then I found this: 0.9% Sodium Chloride Injection, USP contains 9 g/L Sodium Chloride (sodium chloride (sodium chloride injection) injection) , USP (NaCl) with an osmolarity of 308 mOsmol/L (calc). It contains 154 mEq/L sodium and 154 mEq/L chloride.
so that would mean 154/9= 17.1 in .1% Na Cl or 1710 mEq in 10% NaCl (1L)
2.5x 1710=4275 mEq
4275/2=2137.5
Can't find the normal mEq in Mag Sulfate 
Feb 13You got the correct number of mEq of MgS04. I will see if anyone else wants to try before I post the answer.
Brad 

Feb 14You have 2.5 L of 10% NaCl solution and your friend has 1.5 L of MgSO4 solution. You have twice as many mEq of NaCl as your friend has of mEq of MgSO4. What is the percentage strength of your friend's MgSO4?
First, you need to find how many mEq of NaCl you have:
You have twice as many mEq of NaCl as your friend has of mEq of MgSO4. So, you take mEq of NaCl and divide by 2 to get mEq of MgSO4
4,723.5 mEq of NaCl/2 = 2,136.8 mEq of MgSO4.
Now, you need to change 2,136.8 mEq of MgSO4 to grams.
MgSO4 mg/mmol:1 Mg (24.3 x 1) + 1 S (32.1 x 1) + 4 O (16 x 4) = 120.4 mg/mmol
[U]MgSO4 mEq/mmol[/U: Mg and SO4 each have 2 charges = 2 mEq/mmol
Now, percent of solution is g/mL. We know how many L of MgSO4 my friend has (1.5 L). We know how many g of MgSO4 my friend has (128.6 g). We need to change L to mL, and convert into percentage strength.
The percentage strength of my friend's MgSO4 is 8.6%
This is thanks to a little help from your book bjwojcik!!