You have 2.5 L of 10% NaCl solution and your friend has 1.5 L of MgSO4 solution. You have twice as many mEq of NaCl as your friend has of mEq of MgSO4. What is the percentage strength of your friend's MgSO4?
First, you need to find how many mEq of NaCl you have:
You have twice as many mEq of NaCl as your friend has of mEq of MgSO4. So, you take mEq of NaCl and divide by 2 to get mEq of MgSO4
4,723.5 mEq of NaCl/2 = 2,136.8 mEq of MgSO4
Now, you need to change 2,136.8 mEq of MgSO4 to grams.
:1 Mg (24.3 x 1) + 1 S (32.1 x 1) + 4 O (16 x 4) = 120.4 mg/mmol
[U]MgSO4 mEq/mmol[/U: Mg and SO4 each have 2 charges = 2 mEq/mmol
Now, percent of solution is g/mL. We know how many L of MgSO4 my friend has (1.5 L). We know how many g of MgSO4 my friend has (128.6 g). We need to change L to mL, and convert into percentage strength.
The percentage strength of my friend's MgSO4 is 8.6%
This is thanks to a little help from your book bjwojcik!!