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The first one is 200. First you have to turn the fraction into what is called an improper fraction. 4 (1/4) = ((4 × 4) + 1)/4 =17/4. Turn that into a percentage, you have to divide it by 100. Which looks like 17/4 OVER 100/1. Which equals 17/400..then plug that into the p/100 (n) = r equation.
Multiply each side by 400, you get 17n = 8.5 (400). 17n equals 3400. N = 200.
I know I did a BAD job of explaining..but I know someone can probably explain better!
I'm off to class now..will explain the 2nd problem when I get out!
Agrippa
490 Posts
Question is, 4 1/4% of (?) = 8.5.
A. 80.
B. 100.
C. 200.
D. 50.
The way I did this question was as follows:
4 1/4% = 425%. 425% changed to decimal is 4.25. Thus to solve, it is simple algebra: 4.25x=8.5. The answer should be 2, not 200 as the answer keys says it is in the net study guide. Am I missing something here?
Same goes for this problem.
2/3% of (?) = 33.3
A. 5000
b. 400
c. 600
d. 1000
Answer is 50, not 5000 as the answer key says. Am I just fundamentally getting something mixed up here? It has been a while since i did this kind of math so I am a bit rusty. Thanks guys.