Published Jan 22, 2009
Agrippa
490 Posts
Question is, 4 1/4% of (?) = 8.5.
A. 80.
B. 100.
C. 200.
D. 50.
The way I did this question was as follows:
4 1/4% = 425%. 425% changed to decimal is 4.25. Thus to solve, it is simple algebra: 4.25x=8.5. The answer should be 2, not 200 as the answer keys says it is in the net study guide. Am I missing something here?
Same goes for this problem.
2/3% of (?) = 33.3
A. 5000
b. 400
c. 600
d. 1000
Answer is 50, not 5000 as the answer key says. Am I just fundamentally getting something mixed up here? It has been a while since i did this kind of math so I am a bit rusty. Thanks guys.
♥MyTimeWillComeϖ
21 Posts
4 1/4% = .0425 not 4.25
.0425x = 8.5
Answer = 200
Same with the other one.
dohzenOFF
90 Posts
4,1/4% = 4.25% = 0.0425
0.0425x = 8.5
8.5/0.0425 = 200
Thanks...ive gotta get the cobwebs out of my head fast!
Lovelymo79
908 Posts
The first one is 200. First you have to turn the fraction into what is called an improper fraction. 4 (1/4) = ((4 × 4) + 1)/4 =17/4. Turn that into a percentage, you have to divide it by 100. Which looks like 17/4 OVER 100/1. Which equals 17/400..then plug that into the p/100 (n) = r equation.
Multiply each side by 400, you get 17n = 8.5 (400). 17n equals 3400. N = 200.
I know I did a BAD job of explaining..but I know someone can probably explain better!
I'm off to class now..will explain the 2nd problem when I get out!
See!! I knew I took the long way..but it's the only way I know for sure :-)
Finished the exam. Did well . I was only given 30 math questions though...i thought we were supposed to get 60.