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Based on the way this problem is stated I get 1800gtts/hr:

30cc x 60gtt = 1800

1hr...... 1cc ......1

There are 1800 gtts in 1 hr if there are 60 gtts in

a cc and you are giving 30 cc in 1 hour. In the problem you cancel out your cc's and are left with gtts/hr.

I believe this is correct...I'm sure Daytonite will be along to check my work!

I had the same answer. 60 gtt/mL(or cc), wanting 30mL per hour. So restated: there are 60 drops per mil, and we want 30 mils, or 30x60, per hour, which is 1800

30cc/hour (dose to give) x 60 gtts/cc (drop factor of tubing) = 1800 gtts/hour

however, this is not how drip rates are usually calculated in the real world. they are usually stated in terms of gtts per minute, so

1800 gtts/hour x 1 hour/60 minute (conversion factor) =

30 gtts/minute

would seem to me to be the more likely and logical answer to this question. in the actual working world, this would be how this would be answered.

i didn't think this seemed quite right either, i'm glad for your help as always daytonite...we all are!

Can someone help me with problem please:

Given 500cc 1/2 N/S IV to drip at 30cc/hr using a microdrip (60 gtts/cc). How many gtts per hour regulate?

I'm only a 1st semester, so I'm not sure what exactly "regulate?" means; but my answer is 1800 drops per hour.

ie, You've got 60 drops per cc, and you're doing 30 cc per hour...so just multiply 30 x 60.

Then, as others have said, if you wanted to get your drops per minute, just divide 1800 by 60 minutes, which gives you 30 drops per minute.

Was there something in particular in the problem that you're having difficulty with? If so, feel free...perhaps we can elaborate more on it...

30cc/hour (dose to give) x 60 gtts/cc (drop factor of tubing) = 1800 gtts/hour

however, this is not how drip rates are usually calculated in the real world. they are usually stated in terms of gtts per minute, so

1800 gtts/hour x 1 hour/60 minute (conversion factor) =

30 gtts/minute

would seem to me to be the more likely and logical answer to this question. in the actual working world, this would be how this would be answered.

that's accurate with my school as well. we're required to state it in terms of minutes

Thanks, that is the right answer,I just didn't know how to setup the problem or what to use in the problem and what not to use. Sometime there is info in a problem that you don't need and I think that's my problem, knowing what to use and what not to use in a problem.