The recommeneded dose of Mysolin is 10-25 mg/kg/day divided bid. Determine the maximum recommended dose for a 40 pd child in mg. mg/day10-25 mg/kg/day40 pd 2.2 pd/kgmg/day = 10 (25)mg /kg/day x kg /2.2 pd x 40 pd/1 = 182 (455) mg/day min(max) so the maximum would be 455 ? Am I approaching this problem correctly ?
gt4everpn, BSN, RN 724 Posts Specializes in Licensed Practical Nurse. May 20, 2007 first off 40/2.2= 18.18 or 18.2(kg)now lets pick the lowest dose ordered which is 10 mgso- 10 x 18.2 = 182 mg- max dose per day, since the drug has to be given twice a day divide 182/2 = 91 mg each dose.now pick the highest dose ordered which is 25 mgso 25 x 18.2= 455 mg max dose per day, since the drug has to be given twice a day divide 455/ 2= 227.5 mg each dose.so basically the max dose for the day is anywhere btwn 182 mg - 455 mg. each dose or one dose ranges anywhere from 91 mg to 227.5 mg per dose. good luck!
Daytonite, BSN, RN 4 Articles; 14,603 Posts Specializes in med/surg, telemetry, IV therapy, mgmt. Has 40 years experience. May 20, 2007 to compute this you need to convert 10-15/mg/kg/day into what it would be for a 40 pound child. in effect you have two problems to solve:what is the lowest recommended daily dose for a 40 lb child if the recommended dose is 10-25 mg/kg/day?and, what is the highest recommended daily dose for a 40 lb child if the recommended dose is 10-25 mg/kg/day?you know i like to use dimensional analysis to solve these.what is the lowest recommended daily dose for a 40 lb child if the recommended dose is 10-25 mg/kg/day?i want to end up with mg/day in the final answer. 1 kg = 2.2 lb10 mg/1 kg x 1/1 day (these two fractions are the lowest desired daily dose) x 40 lb/1 (weight of child) x 1 kg/2.2 lb (conversion factor) = 181.81 = 182 mg/day (lowest recommended daily dose for a 40 lb child). if divided in bid doses, each dose would be 182/2, or 61 mg.what is the highest recommended daily dose for a 40 lb child if the recommended dose is 10-25 mg/kg/day?again, i want to end up with mg/day in the final answer. 1 kg = 2.2 lb25 mg/1 kg x 1/1 day (these two fractions are the lowest desired daily dose) x 40 lb/1 (weight of child) x 1 kg/2.2 lb (conversion factor) = 454.55 = 455 mg/day (highest recommended daily dose for a 40 lb child). if divided in bid doses, each dose would be 455/2, or 228 mg.the question asks you to determine the maximum recommended dose for a 40mg child. the safe range with the newly computed figures would be 182-455 mg/40 lb/day. therefore, the maximum safe dose would be the 455 mg/day for a 40 pound child.your final answer was correct, but i has having trouble following your set up. it's probably because of the limitations of what we can do with the text on this software.
srg4784 123 Posts May 21, 2007 Thank you both for your input..I'm so ready for tomorrow to get this thing out of the way!!!
Daytonite, BSN, RN 4 Articles; 14,603 Posts Specializes in med/surg, telemetry, IV therapy, mgmt. Has 40 years experience. May 21, 2007 Well done! Did you use dimensional analysis or other techniques?
