IV drip formula

  1. 0
    Does anyone have a formula they use they love?? I'm on break but want to get familiar with the math soon....

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  2. 15 Comments...

  3. 1
    ORnurseCT likes this.
  4. 0
    Dimensional analysis works great for me
  5. 0
    Quote from SweetPEI
    Dimensional analysis works great for me
    This is a great method... just make sure that you set the problem up correctly and it works, every time. I personally could never quite wrap my head around it, but I know how to do it. Everything I've had to do to date has been either a simple math problem or a ratio problem. There are lots of sites out there for med math. The one above "DosageHelp" is really a good site for that stuff.
  6. 1
    A very simple formula that i use
    Fluid divided by time multiplied by drop factor it will be as
    Fluid'/. Time * drop factor
    paigewhitten1991 likes this.
  7. 0
    Quote from Roshni69
    A very simple formula that i use
    Fluid divided by time multiplied by drop factor it will be as
    Fluid'/. Time * drop factor
    Yes, this works well Don't complicate it. For example

    100ml/ over 60 minutes x drop rate (usually 13-15)
  8. 0
    I use:

    ml x gtts / time.

    Works great, and really simple!
  9. 0
    Ok I used the ml x gtt / time... Works great to get your gtt/min... now my question is how do I solve the units/hr, mLs/hr, and how many hours with the IV pump run for.... I've tried different equations and I am LOST!

    I am trying on my own until class starts and I go to tutoring....
  10. 0
    I still use the mlxgtt/time... then to find units/hr just multiply gtt/min x 60min. To find mls/hr just do ml/60min
  11. 0
    I always tell students that they can use whatever formula they like best (I'm not sharing mine here), but if you have a rough idea of what it ought to be, you can recognize a totally off-the-wall wrong answer.

    To address this question: Your units or milligrams or widgets per hour you solve by first knowing how many units, milligrams, or widgets there are in a given volume. Your problem will always give you the information you need to figure that out.

    For example, if you have a solution that is 500,000 widgets per liter, then you can figure out how many widgets per cc here are, right? 500,000 in a liter / 1000cc in a liter.... so 500,000/1000 will tell you that. So you have 500 widgets in a cc. If your problem asks you to give 25,000 widgets per hour, how many cc is that? That would be ... fifty cc.

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