Algebra help please

[Lisa1970]

I have two equations that I just can't figure out. Can someone look and see if they can tell me how to figure them?

16x-8=

x^2x - 6 = 0 then x is ?

I have to be able to solve these for the admission exam on Tuesday Thanks

[PJMommy]

So 2nr has the correct answer? If so, then there is a misprint in this problem (actually in both...but I'll get there). If the answer to the second problem is x=3 or x=(-2) then the problem should read the way 2nr interpreted it: x(squared) - x - 6 = 0. It seems like you are missing a minus sign in the original problem.

As for the first problem, the answer is only 1/2 if the equation is equal to 0. (i.e. 16x - 8 = 0). In the way it is written above, it is actually unsolvable.

:)

PJ

[PJMommy]

By the way, in most programming and computer equations, "^" means "raised to". x^3 is "x raised to the third" or y^8 would be "y raised to the power of 8".

[kwagner_51]

2ner has it right. You MUST factor. Then check it by putting in the -3 where the x is. Then put the +2 where the x is.

Also, anything raised to the zero power is 1 [one].

The easiest way for me to factor, is to consider what numbers will go into the largest number. In this case it is 6. So 3 x 2= 6. The ONLY other on you can use is 6x1=6.

Hope this helps!

[2ner]

:)