Quote from frogger32091
I have three math problems that I need help with. I have the solutions but I do not know how they got them. If anyone can help that would be great. None of my friends seem to be able to help me and every web site that I have been to wants money. I don't want to pay for a tutor just to get three problems answered. Because I cannot write them out as mathematical equations on this site I am writing it out in words in hopes that you can help me.
1. if xy is not equal to 0 and x is not equal to y and x is not equal to -y then
(3/y - 3/x) / 1/y^2 - 1/x^2 = ?
(the ^2 means to the 2nd power in case you did not know)
2. what is the square root of: 2^1 + 2^2 / 2^3 (the entire problem has a square root symbol over)
3. ab-c = cb and a is not equal to c then b=
Again if you can help I would greatly appreciate it. I could not make the sign for not equal to that is why I wrote it out. I have learned over three months of Algebra in a little over a week, and I have greatly improved my scores, but I still have trouble with problems like these that don't seem to make any rational sense. Thank you again for any help you can give me.
oh and the answers that I was given for these problems are:
1. 3xy/x+y
2. square root of 3 over 2
3. b= c/a-c or b= c over a-c
I got the answers from an online algebra calculator, but it would not tell me how it got the answers and so it did not help me any
1.
i would solve for x or y, then substitute to solve for the other.
2.
2^1 + 2^2 / 2^3 (the entire problem has a square root symbol over)
= 2^1 + 2^(-1) (the entire problem has a square root symbol over)
=2 + 1/2 (the entire problem has a square root symbol over)
= 5/2 (the entire problem has a square root symbol over)
sorry, but for the way your question is written, the answer is (5/2)^1/2
it gives me a headache to figure out what you meant to write. srry
3.
ab-c = cb
ab-cb = c
b(a-c) = c
b = c / (a-c)
(or if you want to simply further, you would factor out the c to get c(1/(a-1)) = (c/a) - (c/1) = (c/a) -c