Math Help anyone!!!!

It looks like you've mainly got an order of operations problem there. In other words, you need to figure out what to do first, second, third, etc.

Here's a page that may help:

http://www.purplemath.com/modules/orderops.htm

and then you solve the linear equation for x.

http://www.purplemath.com/modules/solvelin.htm

hope that helps.

It looks like you've mainly got an order of operations problem there. In other words, you need to figure out what to do first, second, third, etc.

Here's a page that may help:

The Order of Operations: PEMDAS

and then you solve the linear equation for x.

Solving One-Step Linear Equations

hope that helps.

Thanks so much, i appreciate it!!

It is an algebra problem, but order of operations is your first order of business. Just remember to take it one step at a time and don't try to do too many parts in one step.

Good luck!

Kathy

I got x=0, is that right?

Now I'm getting nervous about my own lack of recent math experience. I used to be a math geek, but it's been a while. I know the OP wasn't asking for an answer, but did anyone else try to solve it?

I got 0 also! Good job!

I see you solved it. For order of operations I memorized this little acronym: GEMA. It stands for grouping, exponents, multiply and divide, add and subtract.

That little gem has saved me from having to think too hard.

tofutti

I got x=0, is that right?

Now I'm getting nervous about my own lack of recent math experience. I used to be a math geek, but it's been a while. I know the OP wasn't asking for an answer, but did anyone else try to solve it?

yes you are right x=0.

thanks so much everyone for your responses.

i did try to solve the problem on my own before i posted, but i got so confused with the x's

but i think if i understand something like

x + 10x = 11x (in this particular question i mean)

and i would look at "x" as 1x and thats where the 11 comes from???

i got so confused with that

thanks so much again

You are correct - any variable with no number in front of it is considered a "1". The hardest thing to remember it seems is to work parentheses from the inside out and use the distributive property to get rid of them ASAP. They always seem to hose people up.

Take care,

Kathy

Question: x + 2[3 -5(1 - x)] = 3(x-3) + 5

solutions: x+2[3-5(1-x)]=3(x-3)+5

x+2[3-5+5x]=3x-9+5

x+2[-2+5x]=3x-4

x-4+10x=3x-4

-4+11x=3x-4

11x-3x=-4+4

8x=0

x=0

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