Published Feb 1, 2005
dave1117
202 Posts
I have gotten quite good at the whole calculations thing using dimensional analysis. The one question that I know will be on our test next week and I can not find anything in the book is on Enteral Feeding dilutions. Example below...
Ensure is available in 8oz cans. How many cc's of water must be added to 1 can of formula to make 3/4 strength solution?
Any help with the right (or logical) way to remember how to figure this out would be appreciated.
Thanks, dave :)
HappyNurse2005, RN
1,640 Posts
8 oz-240cc's.
if they want 3/4 strength, then they want 3 parts of ensure(the feeding is always the top # of the fraction) to 1 part water(difference btw top adn bottom number is how many parts water), for a total of 4 parts (equal to bottom number of fraction)
so 240cc is 3/4 of what?
240/x = 3/4 cross multiply fractions to get 3x=960 then divide. 960/3=320.
so that makes 320 your total amount of feeding, water included. 240 of that is ensure, 80 is water. you know this is right when you see that 320 divided by 4 parts is 80.
so 80*3=240. your 240 cc can of ensure is 3/4 of the 320, 80cc water is 1/4.
make sense?
Thank you very much...
The answer was there the whole time.
dave :)