# Need help in chemistry AGAIN!!!

1. Ok, here is the problem....

How many kilocalories of energy are trasferred from 1g of butter if burning 10g of butter raises the temperature of 1000g of water in a calorimeter from 20degrees to 90degrees celsius?

Geesh...I hate chemistry!!!!

Joined: Apr '01; Posts: 1,345; Likes: 12
student nurse extern

3. This is the problem that the prof gave us. Does anyone know how to do this...or maybe have a family member that can explain it to me???? PLEASE!!!

How many kilocalories of energy are trasferred from 1g of butter if burning 10g of butter raises the temperature of 1000g of water in a calorimeter from 20degrees to 90degrees celsius?

Geesh...I hate chemistry!!!!
4. If there is a 70 degree C temp change for 10g of butter heating 1000g of water, that would equal a 7 degree C temp change for 1g of butter heating the same 1000g of water. A 7 degree C change of 1000g of water would be equiv to a 7000 calorie exchange (1 calorie will raise the temp of 1g of water 1 degree C) Now you must convert the 7000 calories to kilocalories by dividing by 1000. 7 kilocalories is the answer if my formulas and memory are correct. If not, this at least gives you some direction to go, not.
5. Spud to the rescue again!! Thanks!!

Now all I need is about a size 12-13 shoe up my *** to get me in gear and do all this homework I have this weekend!!!
6. Hope I'm right...or at least close Remember, you can always e-mail me direct. I check my mail frequently. Have fun with your homework. I myself am writing ANOTHER paper.
7. Spud,

I know the feeling with the papers.....got one due on Tuesday....8-10 pages!!! YUK!!

If I can help you with any research let me know....gotten pretty good at surfing the net and if it's there, I'll find it!!
8. Here is the formula you need to use:

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Heat released = (mass)(specific heat) (temp change oC - oC)

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-Knowing that 1.00 cal/g is water's specific heat.
-Divide to find the Kcal for 1g of butter.

Sue
9. GAWD!!!
I just now realized how old that post was!!

Oh well, I'm sure they have gotten the help they needed by now!
10. :chuckle

11. that was a good answer, maybe someone can still use it this semester!
12. Originally posted by bhppy
Here is the formula you need to use:

-------------------------------------------------

Heat released = (mass)(specific heat) (temp change oC - oC)

-------------------------------------------------

-Knowing that 1.00 cal/g is water's specific heat.